Question

A conductor, if the number of conduction electrons per unit volume is 8.5×1028m−38.5×1028m−3 and mean free time is 25 fs (femto second), its approximate resistivity is: (me=9.1×10−31kg)

Answer 1

Answer:

$\rho =\dfrac{m}{ne^2\tau} </p><p> =1.67\times 10^{-8}\Omega m$

Answer 2

Answer:

10^-8 is the answer of this

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