Question

a cone of radius 10 centimetre is cut into two parts by the plane through the midpoint of its vertical Axis parallel to the base find the ratio of the volume of the smaller cone and frustum of the cone​

Answer 1

Answer:

Step-by-step explanation:

As the cone is divided into two equal parts by the axis so, AQ = AP/2

with the help of similarity theory,

QD / PC = AQ / AP

so, QD / PC = 1/2

so, rdius of QD = PC/2 = R/2

now,the volume of frustum = 1/3πR²H - 1/3π(R/2)²(H/2)

                                                = 1/3πR²H*7/8

compare the two parts in cone

1st is the volume of small cone and 2nd the volume of frustum

i.e. (1/3π(R/2)²(H/2))/(1/3πR²H*7/8) = (1/8)/(7/8)=1/7

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