A conical vessel, with base radius 5 cm and height 24 cm, is full of water. This water is emptied
into a cylindrical vessel of base radius 10 cm. Find the height to which the water will rise in the
cylindrical vessel. [Use π=22/7]
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radius of conical vessel=r1=5cm
height of conical vessel=h1=24cm
radius of cylindrical vessel=r2
let water rise upto the height h2 of the cylindrical vessel
volume of water in conical vessel = volume of water in cylindrical vessel
1/3π1rrh1=π2rrh2 (rr means r square)
rr1h1=3rr2h2
5*5*24=3*10*10*h2 (* means multiply)
h2=5*5*24/3*10*10
=2 cm
height of conical vessel=h1=24cm
radius of cylindrical vessel=r2
let water rise upto the height h2 of the cylindrical vessel
volume of water in conical vessel = volume of water in cylindrical vessel
1/3π1rrh1=π2rrh2 (rr means r square)
rr1h1=3rr2h2
5*5*24=3*10*10*h2 (* means multiply)
h2=5*5*24/3*10*10
=2 cm
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