Science, asked by babbycrazbest, 1 year ago

A constant force act on an object of mass 2 kg for 10 second's and increases its velocity from 5m/s to 10 m/s . find magnitude of applied force .if this force was apllied for a duration of 15 sec what will be the velocity of object ?

Answers

Answered by Ishan007
0
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Answered by Anonymous
1

  \bold{Given :-}

  \bold{mass \:  =  \: 10kg}

  \bold{time \:  =  \: 1sec}

  \bold{initial \: velocity \: (u) = 5m/s}

 \bold{final \: velocity (v) \:  = 10m/s}

 \bold \red{acceleration \:  =  \frac{v - u}{t}}

 \bold{a \:  =  \:  \frac{10 - 5}{1} }

 \bold{a \:  =  \: 5m/s²}

 \bold \red{force \:  =  \: m \times a}

 \bold{force \:  =  \: 10kg \:  \times 5m/s²}

 \bold \green{force \:  = 50N.... \:  \:  \: ans}

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