Physics, asked by changulyasaka, 1 year ago


A Constant force acts on a 5Kg object and reduces its velocity from 7m/s to 3m/s in a time of 3s. Calculate:
The force required
The Displacement of the object
Work done on the object
Power
The Kinetic energy

Answers

Answered by Bhumik2209
2
5
 \frac{1}{2} m {v}^{2} = \\ \\ \\ 5 \times {7}^{2} = 245 \\ \\ \\ 5 \times {3}^{2} = 45 \\ \\ \\ = 245 - 45 = 200 \: ans = 200
245-45 =200 and...

changulyasaka: Can u help with the workdone and the power??
Answered by kalproy111
1
Force = - 6.65 N
S = 15.03 m
W = 99.9 N
K.E = 22.5 j

changulyasaka: Can you show the working??
Similar questions