Question

a constant force acts on a body of mass 10kg and produces in it an acceleration of 0.2ms-2. calculate the magnitude of force acting on the body

Answer 1

according to Newton`s 2nd law motion 
force = rate of change of momentum
        = mass× ( rate of change of velocity )
        = mass ×acceleration
       so the magnitude of the force acting on the body is
       ( 10×0.2 )N = 2 N

Answer 2

Answer:

Force acting on the body of mass 10kg is = 2N

Explanation:

Newton's second law of motion states that force acting on a body is proportional to the rate of change of momentum of that body.

force = rate of change of momentum = $\frac{dp}{dt}$

force = mass * ( rate of change of velocity )

       = mass ×acceleration

       = $m*a$  

In the question it is given that:

mass $m=10kg$;      acceleration $a=0.2m/s^2$

so the force acting on the body of mass 10kg is,

$F=10kg*0.2m/s^2\\ \implies F= 2kgm/s^2 \\\implies F= 2N$

Required force = 2N

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