a constant force acts on an object of mass 5 kg for the duration of 2 sec. it increases the velocity from 3m/s to 7m/s. find the magnitude of the applied force
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Answered by
2
10 newton is force applied
rohit710:
pls give steps also
Answered by
14
Heya.....!!!
We know that , F = m(v-u)/t .
By applying this simple formulae we can calculate magnitude of force .
F = 5(7-3)/2
»» 20/2
F = 10 N , is the required answer .
HOPE IT HELPS U
We know that , F = m(v-u)/t .
By applying this simple formulae we can calculate magnitude of force .
F = 5(7-3)/2
»» 20/2
F = 10 N , is the required answer .
HOPE IT HELPS U
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