Question

A constant retarding force of 500 is applied to the body of Mass 200g moving initially with a speed of 15 m/s how long does the body take to stop

Answer 1

hey dear
here is your answer

given data :

force = 500 N

mass = 200 g or 0.2 kg

initial velocity = 15 m/s

final velocity = 0

to find : time taken

solution :

force = mass*acceleration

500 = 0.2*a

a = -2500 m/s^2

by using 1st equation of motion

v = u+at

0 = 15-2500*t

t = 15/2500

t = 0.06 seconds

hope it helps :)

Answer 2

Explanation:

Retarding force, F = –50 N

Mass of the body, m = 20 kg

Initial velocity of the body, u = 15 m/s

Final velocity of the body, v = 0

Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:

F = ma

–50 = 20 × a

∴ a = -50/20 = -2.5 ms-2

Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as:

v = u + at

∴ t = -u / a = -15 / -2.5 = 6 s