A constant retarding force of 500 is applied to the body of Mass 200g moving initially with a speed of 15 m/s how long does the body take to stop
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Answered by
0
hey dear
here is your answer
given data :
force = 500 N
mass = 200 g or 0.2 kg
initial velocity = 15 m/s
final velocity = 0
to find : time taken
solution :
force = mass*acceleration
500 = 0.2*a
a = -2500 m/s^2
by using 1st equation of motion
v = u+at
0 = 15-2500*t
t = 15/2500
t = 0.06 seconds
hope it helps :)
here is your answer
given data :
force = 500 N
mass = 200 g or 0.2 kg
initial velocity = 15 m/s
final velocity = 0
to find : time taken
solution :
force = mass*acceleration
500 = 0.2*a
a = -2500 m/s^2
by using 1st equation of motion
v = u+at
0 = 15-2500*t
t = 15/2500
t = 0.06 seconds
hope it helps :)
Answered by
3
Explanation:
Retarding force, F = –50 N
Mass of the body, m = 20 kg
Initial velocity of the body, u = 15 m/s
Final velocity of the body, v = 0
Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:
F = ma
–50 = 20 × a
∴ a = -50/20 = -2.5 ms-2
Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as:
v = u + at
∴ t = -u / a = -15 / -2.5 = 6 s
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