Question

A contractor undertook a job and employed 40 men to do a piece of work in 80 days. But after 60 days he found that only 3/5 of the work is completed. To complete the work in time, how many more men he should employ ?

Answer 1

40 can do a piece of work in 80 days

they worked for 60 dAys = 3/5*60

1/36

remaining work

1 - 1/36

35/36

now'

35/36*80

solve this equation

Answer 2

40 additional men are required.

Step-by-step explanation:

Consider the provided information.

Use the formula: $\dfrac{M_1D_1H_2}{W_1} =\dfrac{M_2D_2H_2}{W_2}$

Where M represents the number of employees, D represents the number of days, H represents the hours and W represents the part of work done.

It is given that 3/5 th of work is completed in 60 days, Now contractor need to complete the $1-\frac{3}{5} =\frac{2}{5}$ th of work in 80-60=20 days.

Let x is the total number of employees required.

Substitute the respective values in the above formula.

$\dfrac{40\times60}{\frac{3}{5}} =\dfrac{20\times x}{\frac{2}{5}}$

$\dfrac{40\times60}{3} =\dfrac{20\times x}{2}$

$x=4\times20$

$x=80$

Total number of men required is 80 but they already has 40.

So the additional men required are: 80-50=40.

Hence, 40 additional men are required.

#Learn more

A contractor undertook to do a certain work in 75 days and employed 60 men to do it. after 25 days he found that only one-fourth of the work was done. how many more men must be employed in order that the work may be finished in time?

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