a converging lens has its focal length as 10cm and an object of 5cm length is placed at a distance of 15cm from the lens find the nature position and size of the image draw the ray diagram
Answers
Answer:
Real and inverted.
Explanation:
Given,
Height of object =5cm
Position of object, u=−25cm
Focal length of the lens, f=10cm
Position of image, v=?
We know that,
v
1
−
u
1
=
f
1
v
1
+
25
1
=
10
1
v
1
=
10
1
−
25
1
So,
v
1
=
50
(5−2)
That is,
v
1
=
50
3
So,
v=
3
50
=16.66cm
Thus, distance of image is 16.66cm on the opposite side of lens.
Now, magnification =
u
v
That is,
m=
−25
16.66
=−0.66
Also,
m=
heightofobject
heightofimage
or
−0.66=
5cm
heightofimage
Therefore, Height of image =3.3cm
The negative sign of the height of image shows that an inverted image is formed.
Thus, position of image is at 16.66cm on opposite side of lens.
Size of image =−3.3cm at the opposite side of lens
Nature of image is real and inverted