Physics, asked by elangosangeetha1985, 1 month ago

a converging lens has its focal length as 10cm and an object of 5cm length is placed at a distance of 15cm from the lens find the nature position and size of the image draw the ray diagram ​

Answers

Answered by gotikarati
0

Answer:

Real and inverted.

Explanation:

Given,

Height of object =5cm

Position of object, u=−25cm

Focal length of the lens, f=10cm

Position of image, v=?

We know that,

v

1

−  

u

1

=  

f

1

 

v

1

+  

25

1

=  

10

1

 

v

1

=  

10

1

−  

25

1

 

So,

v

1

=  

50

(5−2)

 

That is,

v

1

=  

50

3

 

So,

v=  

3

50

=16.66cm

Thus, distance of image is 16.66cm on the opposite side of lens.

Now, magnification =  

u

v

 

That is,

m=  

−25

16.66

=−0.66

Also,

m=  

heightofobject

heightofimage

 

or

−0.66=  

5cm

heightofimage

 

Therefore, Height of image =3.3cm

The negative sign of the height of image shows that an inverted image is formed.

Thus, position of image is at 16.66cm on opposite side of lens.

Size of image =−3.3cm at the opposite side of lens

Nature of image is real and inverted

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