a copper cube with edge 27cm is melted and made into smaller cubes each having edge of 9cm. how many such small copper cubes do we get?
Answers
Answered by
20
Solution :
Edge of the copper cube ( x ) = 27cm
edge of smaller cube ( y ) = 9 cm
If copper cube is melted and made
smaller cubes .
Let the number of smaller cubes = n
n = ( volume of big cube )/( volume of smaller
cube )
=> n = x³/y³
=> n = ( x /y )³
=> n = ( 27/9 )³
=> n = 3³
Therefore ,
n = 27
••••
Edge of the copper cube ( x ) = 27cm
edge of smaller cube ( y ) = 9 cm
If copper cube is melted and made
smaller cubes .
Let the number of smaller cubes = n
n = ( volume of big cube )/( volume of smaller
cube )
=> n = x³/y³
=> n = ( x /y )³
=> n = ( 27/9 )³
=> n = 3³
Therefore ,
n = 27
••••
Answered by
10
Hey,
Initial length of the edge of the copper cube = A = 27 cm
Initial volume of the copper cube = (A)³ = (27)³ = 19683 cm³
Now ,
After making smaller cubes , length of edge of each small cube = a = 9 cm
So, new volume (i.e. volume of each small cube) = (a)³ = (9)³ = 729 cm³
Let the number of small cubes be p
The volume of the initial cube = p × volume of each small cube
⇒19683 = p× 729
⇒p = 19683/729
⇒p = 27
So , the total number of small cubes is 27.
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