A copper rod of diameter 2 and lenght 10 cm is drawn into a wire of uniform thickness and lenght 10 m.Find the thickness of the wire.
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Given diameter of the copper rod = 2 cm
So, radius(r) of the copper rod = 1 cm
Let R is the radius of the cross section(circular) of the wire.
Now, according to the question,
πR2 *(10 * 100) = π(1)2 *10
=> R2 *(1000) = (1)2 *10
=> R = 0.1
Now, thickness of the wire = 2r = 2 * 0.1 = 0.01 cm
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