A copper wire has a resistance of 0.5 ohm .Another copper wire of the same mass as the first is doubled in length of the first .Find the resistance of the second wire
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Answer:
R = 0.5
R = ∫l/a
0.5 = ∫l/a → ( equation 1 )
R1 = ∫2l/a
R1 = 2∫l/a
R1 = 2 × 0.5 ( because from equation 1 0.5 = ∫l/a)
R1 = 1.0
therefore resistance of second wire = 1.0 ohm
Explanation:
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