A copper wire has diameter 0.5 mm and resistivity of 1.6 x 10 power -8 ohm m .what will be
the length of this wire to make its resistance 10 ohm How much does the restane
change of the diameter is doubled
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The resistivity is, ρ=1.6×10−8Ωm . Now, let us assume the length of the wire needed to make its resistance 10Ω is l. Here, R is the resistance of the wire, ρ is the resistivity, l is the length and A is the area. Therefore, the length of the wire to make the resistance 10 ohm is 122 m.
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