a copper wire of resistivity 1.63*10^-8 has cross section area of 10.3*10^-4cm ^2.calculate thelength of the wire required to make a 20 ohm coil.
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R = ρL/A
L = RA/ρ
L = 20 * π * (10.3 * 10^-6)^2 / (1.63 * 10^-8)
L = 0.40 m
Length of the wire should be 0.40 m
L = RA/ρ
L = 20 * π * (10.3 * 10^-6)^2 / (1.63 * 10^-8)
L = 0.40 m
Length of the wire should be 0.40 m
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