A copper wire of resistivity 2.6×10^-3 ohm meter, has a cross sectional area of 30×10^-4 cm^3.calculate the length of this wire required to make a 10ohm coil
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Answer:
62.5
Explanation:
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Answer:
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Explanation:
Given,
R=10Ω
A=10×10
−8
m
2
ρ=1.6×10
−8
Ω/m
We know that,
R=ρ
A
l
l=
ρ
RA
=
1.6×10
−8
10×10×10
−8
l=62.5m
The length of wire copper wire is 62.5m
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