Math, asked by sachinlamba5550, 11 months ago

A corrupt milkman bought 8 l of milk at the cost of 50 per l and mixed 2 l of water with it and sold the mixture at 60 per l, then his gain percentage in the process is

Answers

Answered by beenabaghel1983
1

Answer:

50 % gain

Step-by-step explanation:

cost price of milk = 50×8 = 400

sold price of milk = 60×10 = 600

PROFIT = 600 - 400 = 200

SO, PROFIT% = 200/400 × 100

= 50%

Answered by varshajain46
0
COST PRICE ON 8L => ₹(50x8)
= ₹400
SELLING PRICE ON 10L => ₹(60x10)
= ₹600
PROFIT => SP-CP
= ₹(600-400)
= ₹200
PROFIT % => PROFIT/CPx100
= (200/400x100)%
= (2/4x100)%
= (100/2)%
= 50%


THEREFORE PROFIT% IS 50%
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