A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs. 90, find the number of articles produced and the cost of each article.
Answers
The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs 750.
Answer:
Given: The total cost of production- Rs.
Let the number of pottery articles
produced bex
Therefore, cost of production of each
article Rs (2x + 3)
the total cost of production no.
of pottery articles produced cost of
production
A.TQ
90. X(2x + 3) 0
► 2x + 3x - 900
► 2x715x 12x 90 0
> x(2x + 15) 6(2x +15) 0
-> (2x +15)(x - 6) = 0
Now 2x+15 02x - 15
>x= -15/2
>= 15/2 or x = 6
As the number of articles produced can
only be a positive integer, therefore,
can only be 6
________________________________
Hence, number of articles produced - 6
Hence, number of articles produced - 6Cost of each article=2*6 + 3 Rs 15.
________________________________
Hope this will help you...