Question

A cricket ball is thrown at a speed of 28m/s ,in a direction 30degree above the horizental..calculat maximum height

Answer 1

Maximum height = (V sin0)² / 2g 
= (28 sin30)²/ 2 x 9.8

= 14 x 14 / 2 x 9.8
= 10m

Answer 2

maximum height = (V sin(theta))² / 2g
= (28 sin30)²/ 2 x 9.8

= 14 x 14 / 2 x 9.8
= 10m