Question

a cricket ball is thrown up with a speed of 19.6 M per second inverse the maximum height it can reach its

Answer 1

initial velocity=19.6m/sec

$use \: equation \: of \: motion \\ \\ {v}^{2} - {u}^{2} = 2 ( - g)(h) \\ 0 - {(19.6)}^{2} = - 2gh \\ h = \frac{ {(19.6)}^{2} }{9.8 \times 2}$solve calculation poetion by yourself...

Answer 2

Answer:

Explanation:

Refer the below attachment.