Question

A cricket ball of mass 100gm is travelling at 30m/s. It strikes a bat and travels back at the same speed. How much change in momentum foes the bat suffer? State the law of conservation of momentum
Plz gimme the answer fast

Answer 1

${\mathbb{\pink{Hola!!!}}}$

${\bf{\green{\underline{Law\:of\: conservation\:of\:momentum}:-}}}$ states the sum of momenta of two objects before collision is equal to the sum of momenta of those objects and there is no external unbalanced Force acting on them.

Given:-

Mass(m)=100g
Velocity (v)=30m/s

Momentum (p)=?

P=mv
P=100×30
P=3000kgm/s

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Answer 2

${\huge {\mathfrak {\red {Answer :-}}}}$

Mass of the cricket ball = 100 gm = 0.1 kg.

Initial Velocity = 30 m/s.

Thus, initial momentum = (0.1 * 30) = 3 kg.m.s^-1

Now, the ball travels back at the same speed. So, the velocity will be same but in opposite direction.

Thus, velocity = - 30 m/s

Now, final momentum = 0.1 * (-30) = - 3 kg.m.s^-1

Therefore, we have

➡️ The change in momentum that the bat suffers is

= initial momentum - final momentum

= 3 - ( - 3) kg.m.s^-1

= 3 + 3 kg.m.s^-1

= 6 kg.m.s^-1

➡️ Hence, the change in momentum that the bat suffers is 6 kg.m.s^-1.

$<i><marquee>❤️Lots of love❤️ </marquee></i>$

➡️ Just kidding ⬅️☺️

$<b>$ That's it.

${\red {Arnab \: here.. }}$

${\huge {\mathbb {\blue {Thanks}}}}$