A cricket ball of masst 120 g moving with a speed of 100m/s piercs through a sack of sand 10 cm thick and comes out with a velocity of 60m/s. Determine the average force exerted by the sand on ball..
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If “a” is retardation then,
a = (u^2 - v^2)/(2S)
a = (100^2 - 60^2) / (2 * 10 * 10^-2)
a = 3200 m/s^2
F = ma
F = 120 * 10^-3 * 32000
F = 3840 N
Average Force exerted by sand is 3840N
a = (u^2 - v^2)/(2S)
a = (100^2 - 60^2) / (2 * 10 * 10^-2)
a = 3200 m/s^2
F = ma
F = 120 * 10^-3 * 32000
F = 3840 N
Average Force exerted by sand is 3840N
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