Question

A cricket player has an average score of 30 runs for 42 innings played by him. in an innings, his highest score exceeds his lowest score exceeds his lowest score by 100 runs. if these two innings are excluded, his average of the remaining 40 innings is 28 runs. his highest score in an innings is

Answer 1

total runs = average*no. of matches
total runs scored in 42 innings = 30*42 = 1260 runs
total runs scored in 40 innings = 28*40 = 1120 runs
so, highest + lowest score       = 1260-1120 = 140 runs
            highest score               = 140 - lowest score
given that,
highest score = lowest score + 100 
 140 - lowest score = lowest score + 100
 140 - 100 = lowest score + lowest score
40 = 2*lowest score
lowest score = 20 runs
highest score = lowest score + 100 = 20+100 = 120 runs
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Answer 2

Answer :

120

Step-by-step explanation:

Avg. of 42 innings 30 runs

Sum of 42 innings 30 × 42 = 1260

Avg of 40 innings 28 runs

Sum of 40 innings 28 × 40 = 1120

His score in last 2 innings = ( 1260 - 1120) = 140 runs

so, (max + min) score = 140 runs

and, according to question ,

(max + min) score = 100 runs

then,

max - min = 140

max + min = 100

2max =240

max = 120

so, his highest score in an innings is 120 runs.