After travelling 25 km the speed of the car increases by 1/4th of its original speed, due to this the car reaches 30 minutes earlier on its destination. if the speed of the car increased 10 km before, then it reaches to its destination 32 2 5 minutes earlier. then find the distance travelled by car
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Answered by
5
distance = speed × time
25/10 = speed × 30
30/2.5 = speed
12 = speed
speed increased = 12/1×4 = 48
distance = 48 × 30
= 1440 km
The distance travelled by the car is 1440 km
25/10 = speed × 30
30/2.5 = speed
12 = speed
speed increased = 12/1×4 = 48
distance = 48 × 30
= 1440 km
The distance travelled by the car is 1440 km
Answered by
5
Answer:
150km
Explanation:
Case first=
Speed=4:5
Time=5:4
1=======30minute
5=======150minute
Second case=5:4
1======162/5
5======162minute
Difference in time due to 10km distance increased=
162-150=12minute
Speed=10/1/5=50km/h
Distance covered in 150 minute
With speed of 50km/h
=====50×5/2=125
Total Distance=125+25=150km
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