Question

A cube having side 10cm is placed on
the table mass of the cube is 10 kg. then.
the pressure exerted by the cube on the
table is. - - -
I) O. I pa 2) loo pa. 3) 980 pa. 4) 9800 pa​

Answer 1

Answer:

0.1pa

Explanation:

Pressure applied=Mass÷Total surface area

Area of surface of cube=10×10=100cm

So, pressure=10÷100=0.1pa

Answer 2

HII FRIEND HERE IS YOUR ANSWER:-

$side \: of \: cube \: = 10cm \\ \\ therefore \: area \: of \: its \: side \: = {10}^{2} = 100 {cm}^{2}$

Now,

$mass \: of \: cube \: = 10kg \\ \\ so \: \: \: \: force \: acting \: on \: it = 10 \times g = 10 \times </em><em>9</em><em>.</em><em>8</em><em> = 98 \: newtons$

Hence,

$pressure \: = \frac{98}{100} = 0.98pascals$ = 0.1pascals

Thanks