Math, asked by Dakshsms2020, 11 months ago

A CUBE IS HAVING FOUR OF ITS FACES COLOURED WITH BLUE GREEN YELLOW RED UNIFORMILY. REMAINING TWO FACES ARE BICOLOURED. HALF OF ONE IS PAINETED RED AND HALF IS BLUE SIMILARLY HALF OF ANOTHER IS PAINTED WITH GREEN AND HALF IS YELLOW. THE LINE SEPARATING THE COLOURS ON FACE IS DIAGONAL. NOW THIS CUBE IS CUT INTO 125 CUBES OF EQUAL DIMENTION.

1 AT MOST HOW MANY CUBES CAN HAVE MORE THAN THREE COLOURS ON ITS FACE?
a] 0
b] 8
c] 4
d] 2

2 AT MOST HOW MANY CUBES CAN HAVE EITHER RED OR GREEN COLOUR ON IT?
a] 73
b] 68
c] 6
d] 80

3 AT LEAST HOW MANY CUBES CAN HAVE BLUE AND YELLOW ON IT?
a] 2
b] 5
c] 9
d] 0

Answers

Answered by js403730
0

Answer:

1. b

2. c

3. a

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Answered by Madalasa22
1

Step-by-step explanation:

1. b

2. c

3. a

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