Question

A cube of copper whose edge 12cm is melted and recast into a cylindrical wire of diameter 0.7cm. what length of the wire will be obtained from the cube?

Answer 1

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Answer 2

The length of the wire = 4488.31 cm

Step-by-step explanation:

Given,

A cube of copper whose edge(a) = 12cm and

The diameter of cylindrical wire (d) =  0.7 cm

∴ The radius of cylindrical wire (r) =  0.35 cm

To find, the length of the wire = ?

∴ The volume of cube = 12 × 12 × 12 = 1728 $cm^{3}$

The volume of cylindrical wire $=\pi r^{2}h$

= $\dfrac{22}{7} \times 0.35\times0.35\times h$

According to question,

The volume of cylindrical wire = The volume of cube

$\dfrac{22}{7} \times 0.35\times0.35\times h$ = 1728

⇒ 22 × 0.05 × 0.35 × h = 1728

⇒ 0.385 × h = 1728

⇒ h = 4488.31 cm

Hence, the length of the wire = 4488.31 cm