a cube of edge length 10 cm is placed inside a liquid. the pressure at the upper face of the cube is 1500 pa. find the force exerted by the liquid on this face?
Answers
Answered by
23
we know that F =PA
P=1500
A= (0.1)(0.1) =0.01
F=(1500)(0.01)=15N
P=1500
A= (0.1)(0.1) =0.01
F=(1500)(0.01)=15N
Answered by
16
given, P=1500, i.e. P=F/A=1500
now, A=.1*.1=.01
so, F =P*A=1500*.01= 15N
now, A=.1*.1=.01
so, F =P*A=1500*.01= 15N
Similar questions