A cube shaped block has edges that are 3 inches long. A larger block has edges that are twice as long. Compare the surface area of the smaller block to the surface of area of the larger block. Support your answer.
Answers
Answered by
1
the larger cube has a surface area of 216 and that of smaller cube has 54
Answered by
3
Surface area of smaller cube = 3×3×6
=9×6
=54inchsq
Surface area of larger cube=6×6×6
=36×6
=216
Surface area of small cube ÷Surface area of large cube =54÷216
=1÷4
=9×6
=54inchsq
Surface area of larger cube=6×6×6
=36×6
=216
Surface area of small cube ÷Surface area of large cube =54÷216
=1÷4
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