A cubic polynomial p(x) such that p(1) = 1, p(2)= 2, p(3) = 3 , p(4) = 5 then p(6) is
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Given
p(1)=1
p(2)=p(1)+p(1)=1+1=2
p(3)=p(1)+p(2)=1+2=3
p(6)=p(2)+p(4)=2+5=7
I hope this will help you ....
p(1)=1
p(2)=p(1)+p(1)=1+1=2
p(3)=p(1)+p(2)=1+2=3
p(6)=p(2)+p(4)=2+5=7
I hope this will help you ....
sanjana87:
p(x)=k(x-1)(x-2)(x-3)+x
we can find k from
p(4)=k(4-1)(4-2)(4-3)+4=5
k=1/6
now plug in x=6
we get
p(x)=(6-1)(6-2)(6-3)/6+6=5
*4*3/6+6=10+6=16
now its ok
thanks
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