Question

A cubical block of side 7 cm is surmounted by a hemisphere. What is the surface area of the

resulted solid?​

Answer 1

Answer:

333.465 or 333.47

Step-by-step explanation:

We have,

Side of cubical block=7cm.

Then radius of hemisphere =27cm=3.5cm.

Then,

Total surface area of the solid=Total surface area of cube-Area of base of hemisphere +curved surface area of hemisphere.

⇒TSA=6×72−π×(3.5)2+2π(3.5)2

⇒TSA=332.465cm2.

Hence, this is the answer.