A cubical block rests on a plane of u=root 3 the angle through which the plane be inclined to the horizontal so that the block just slides down will be
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Answered by
75
using formula
tan(theta)=coefficient of friction (u)
tan(theta) = √3
theta(angle)=60
tan(theta)=coefficient of friction (u)
tan(theta) = √3
theta(angle)=60
Answered by
32
By using the formula,
Tan ¤ = mue (u)
We get,
Tan ¤ = √3
=> ¤ = 60•
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