Question

a cubical block side 5 cm has a mass of 50 kg, then the pressure exerted by the block on a surface is [g =10 m/sec²]


options are


20000 pa

200000 pa

200 pa

1000 pa​

Answer 1

Answer:

The pressure applied by the cubical block of side 5cm and mass 50 kg on the surface will be 200000 Pa

Given,

Mass of the block = 50kg

Side length of the block = 5cm

= 0.05m

Acceleration due to gravity (g) = 10 m/s^2

To find,

Pressure exerted by the block on the surface

Solution

Area of the block = 0.05m × 0.05m = 0.0025m^2

We know that,

Force = m×g

= 50×10

= 500 N

and Pressure = Force/Area

= 500/0.0025

= 200000Pa

Hence, the pressure applied by the cubical block of side 5cm and mass 50 kg on the surface will be 200000 Pa.