a cubical cistern can contains 729 liters find the area of its base.
Answers
Answered by
64
the volume of cistern is 729.
side³=729
side=√729
side=9
the bottom of the cistern must be a square.
area of base=side*side
=9*9=81 unit square
side³=729
side=√729
side=9
the bottom of the cistern must be a square.
area of base=side*side
=9*9=81 unit square
Answered by
29
The area of it's base is 8100 cm².
Given data :
Volume = 729 litres = 729000 cm³
Let, the side = a cm
So,
a³ = 729000
a = 90
So, it's one side = 90 cm
Base area = (90×90) = 8100 cm² (answer)
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