A cuboidal shaped slab of iron whose dimensions are 55cm×40cm ×15cm is melted and recast into a pipe. the outer radius and thickness of the pipe are 4cm and 1cm respectively. find the length of the pipe
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Answered by
5
The volume of the slab is equal to the volume of the pipe
The inner radius of the pipe=4-1=3cm
55*40*15=πh(4²-3²)
h=(55*40*15*7)/22*7=5*20*15=1500cm=15m
Therefore the length of the pipe is 15m
The inner radius of the pipe=4-1=3cm
55*40*15=πh(4²-3²)
h=(55*40*15*7)/22*7=5*20*15=1500cm=15m
Therefore the length of the pipe is 15m
Answered by
3
volume of pipe=volume of cuboidal
pie (Rsq_rsq)h=55×40×15
(22÷7)(4sq_3sq)h
=55×40×15
(22÷7)(16_9)h=55×40×15
(22÷7)7h=55×40×15
22×h=55×40×15
h=1500cm
h=15m
pie (Rsq_rsq)h=55×40×15
(22÷7)(4sq_3sq)h
=55×40×15
(22÷7)(16_9)h=55×40×15
(22÷7)7h=55×40×15
22×h=55×40×15
h=1500cm
h=15m
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