Question

a current of 0.5 ampere is drawn by a filament of an electric bulb for 10 minutes the amount of electric charge flowing through the bulb is
a:400c,b:500c,c:300c and d:600c​

Answer 1

Answer:

current, I = 0.5 A

time, t = 10 minute = 10×60 = 600 seconds

let the total charge flown = Q

\begin{lgathered}I= \frac{Q}{t} \\ \\Q=I*t\\ \\Q=0.5*600\ C\\ \\Q =\boxed{300\ C}\end{lgathered}I=tQQ=I∗tQ=0.5∗600 CQ=300 C  

Answer 2

Answer:

The amount of electric charge that flows through the circuit is 300 C.

Explanation:

Given,

Current (i) drawn by a filament = 0.5 A

Time (t) = 10 minutes = 10* 60 sec = 600 seconds

To find: the amount of electric charge that flows through the circuit.

Solution:

Charge is equal to the product of current and time.

i.e Q = it

here, i = 0.5 A , t = 600 sec

Substituting the values,

Q = 0.5 * 600

or, Q = 300 coulomb

Therefore, The amount of electric charge that flows through the circuit is 300 C.