Question

find the value of k if x - 1 is a factor of p(x) =2x²+kx+√2​

Answer 1

$\mathfrak{\huge{\red{ANSWER}}}$

$p(x) = 2 {x}^{2} + kx + \sqrt{2} \\ \\ = \geqslant p( - 1) = 2( - 1) {}^{2} + k \times - 1 + \sqrt{2} \\ \\ = \geqslant p( - 1) = 2 \times 1 - k + \sqrt{2} \\ \\ = \geqslant p = 2 - k + \sqrt{2} \\ \\ = \geqslant k = 2 + \sqrt{2}$

Answer 2

Answer:

k=-(2+√2)

Step-by-step explanation:

It can be solved by the principle that

If x-a is a factor of f(x) then f(a)=0