Physics, asked by rottengaming77, 24 days ago

A current of 1.0 ampere is flowing in a conductor. The number of electrons passing per second will be:Immersive Reader


(a) 6.25

(b) 6.25 × 10^18

(c) 6.5 × 10^-18

(d) 1

Answers

Answered by Rohit57RA
0

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(d) 1 is the right answer.

Answered by rudrakansari789
0

Answer:

6.25*10^18

Explanation:

I=q/t

so q=I*t

ne=1 (I=1,t=1)

n=1/1.6*10^-19 (e=1.6*10^-19)

n=6.25*10^18

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