Physics, asked by KamleshMahaseth311, 9 months ago

A current of 1 A is passed through two resistances 1Omega and 2Omega connected in parallel. The current flowing through 2Omega resistor will be

Answers

Answered by hashy9
1

Explanation:

total resistance in parallel

R'= 2×1 /2+1= 2/3

as V=IR

so V =1 × 2/3 =2/3 volt

then current I = V/R

current through 2 ohm resistor

I2 = 2/3 /2 = 2/6

=1/3 ampere =0.66 A

hope it helps

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