A current of 1 A is passed through two resistances 1Omega and 2Omega connected in parallel. The current flowing through 2Omega resistor will be
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Explanation:
total resistance in parallel
R'= 2×1 /2+1= 2/3
as V=IR
so V =1 × 2/3 =2/3 volt
then current I = V/R
current through 2 ohm resistor
I2 = 2/3 /2 = 2/6
=1/3 ampere =0.66 A
hope it helps
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