Question

A current of 1 A is passed through two resistances 1Omega and 2Omega connected in parallel. The current flowing through 2Omega resistor will be

Answer 1

Explanation:

total resistance in parallel

R'= 2×1 /2+1= 2/3

as V=IR

so V =1 × 2/3 =2/3 volt

then current I = V/R

current through 2 ohm resistor

I2 = 2/3 /2 = 2/6

=1/3 ampere =0.66 A

hope it helps