Physics, asked by naveenyadu27, 10 months ago

A current of 10A is passing through a long wire which has
semicircular loop of the radius 20cm as shown in the figure.
Magnetic field produced at the centre of the loop is
[Orissa JEE 2003]

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Answers

Answered by sachinrussel
4

Answer:

☺️☺️☺️☺️D is the. answer

Answered by minku8906
9

The magnetic field produced at the center of the loop is  B = 5 \pi  \mu T

Explanation:

Given :

Current passing through the loop I = 10 A

Radius of the loop R = 20 \times 10^{-2} m

From the biot-savert law, magnetic field in current carrying loop is given by,

   B = \frac{\mu _{o } I  }{2 R}

Where \mu _{o} = 4\pi  \times 10^{-7}

In our example loop is half so our above equation is modified as follows,

   B = \frac{\mu _{o } I  }{4 R}

   B = \frac{4 \pi  \times 10^{-7} \times 10 }{4 \times 20 \times 10^{-2} }

   B = 5 \pi  \mu

Hence, The magnetic field produced at the center of the loop is  B = 5 \pi  \mu T

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