Question

A current of 10A is passing through a long wire which has
semicircular loop of the radius 20cm as shown in the figure.
Magnetic field produced at the centre of the loop is
[Orissa JEE 2003]

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Answer 1

Answer:

☺️☺️☺️☺️D is the. answer

Answer 2

The magnetic field produced at the center of the loop is  $B = 5 \pi \mu$ T

Explanation:

Given :

Current passing through the loop $I =$ 10 A

Radius of the loop $R = 20 \times 10^{-2}$ m

From the biot-savert law, magnetic field in current carrying loop is given by,

   $B = \frac{\mu _{o } I }{2 R}$

Where $\mu _{o} = 4\pi \times 10^{-7}$

In our example loop is half so our above equation is modified as follows,

   $B = \frac{\mu _{o } I }{4 R}$

   $B = \frac{4 \pi \times 10^{-7} \times 10 }{4 \times 20 \times 10^{-2} }$

   $B = 5 \pi \mu$

Hence, The magnetic field produced at the center of the loop is  $B = 5 \pi \mu$ T