Question

A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is(a) 2 Wb(b) 0.5 Wb(c) 12.5 Wb(d) Zero

Answer 1

since flux= magnetic field × area ×cos(theta)

where theta is the angle between them

here in this case

theta=0 so

cos(theta)=1

hence

$flux = 2.5 \times 5 \\ = 12.5$

therefore (c) is the correct option

Answer 2

Given that,

Current, I = 2.5 A

Inductance of the coil, L = 5 H

To find,

The magnetic flux linked with the coil.

Solution,

The self inductance of the coil is directly proportional to the current through the coil. Mathematically, it is given by :

$\phi=LI$

$\phi$ is magnetic flux

$\phi=5\times 2.5\\\\\phi=12.5\ \Wb$

So, the magnetic flux linked with the coil is 12.5 Weber.

Learn more,

Inductance

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