Question

A long solenoid of diameter 0.1 m has 2 × 10⁴ turns per meter. At the centre of the solenoid, a coil of 100 turns and radius 0.01 m is placed with its axis coinciding with the solenoid axis. The current in the solenoid reduces at a constant rate to 0 A from 4 A in 0.05 s. If the resistance of the coil is 10π²Ω. The total charge flowing through the coil during this time is:-(a) 16 μC(b) 32 μC(c) 16π μC(d) 32π μC

Answer 1

Answer:

The total charge flowing through the coil during this time is 32 μC.

Explanation:

The total charge flowing through the coil during this time is given by Δ Q.

Δ Q = μ₀ ni π r² / R

Δ Q = 4π x 10 ⁻⁷ x 100 x 4π x 0.01² / 10 π²

Δ Q = 32 μC

Answer 2

Answer:

b) 32 μC

Explanation:

Diameter of solenoid = 0.1m (Given)

Turns of solenoid = 2 × 10⁴ (Given)

Turns of the coil = 100 (Given)

Radius of the coil = 0.01m (Given)

Resistance = R = 10π²Ω

e = -NdФ/dt

e/R = N/RdФ/dt

Δq/Δt = N/RΔФ/Δt

Δq = μoniπr²/R

Δq = 4π × 10~-7 × 100 × 4π × (0.01)²/ 10π²

Δq = 32

Thus, the total charge flowing through the coil during the time is 32 μC