Question

A current of 2a passes through a coil of 100ohm resistance for 5 minutes.Find the heat

Answer 1

Answer:

H = 1.2x 10∧4 J

Explanation:

I = 2A

R = 100 ohm

t = 5x60 = 300 s

H = I²Rt

H = 2² x 100 x 300

H = 1.2x 10∧4 J

Answer 2

Answer: Heat generated = $1.2 * 10^{4} Joule$

Explanation:

• Given parameters,

current = $2Ampere$

Resistance of coil =$100 ohm$

Time taken = $5 minutes$              $(1 minute = 60 seconds)$

                   $=5 * 60 seconds$

                   $= 300 seconds$

• we know

$H= I^{2} RT$

$H = 2^{2} *100* 300$

$H= 12 *10^{4} Joule$

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