A current of 4A is flowing in a copper wire. If the same current is allowed to flow through another copper wire of double the radius, what is the effect on the drift velocity of free electrons?
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Answered by
3
I=4A
we know that,
R∞length/ area
when we double the length the resistance will increase.
V=IR
V/R= I
so, when we double the length then the current will become half. i.e.2 A
= R'=2R= 2L/A
= V/R=4
= V/R'=V/2R=I'
I'= 2A
we know that,
R∞length/ area
when we double the length the resistance will increase.
V=IR
V/R= I
so, when we double the length then the current will become half. i.e.2 A
= R'=2R= 2L/A
= V/R=4
= V/R'=V/2R=I'
I'= 2A
Answered by
1
drift velocity = v_drift = I/neA
n = num of free electrons in unit volume
e = electron charge
A = area of cross section
I = current
drift velocity becomes 1/4 times as the area becomes 4 times.
n = num of free electrons in unit volume
e = electron charge
A = area of cross section
I = current
drift velocity becomes 1/4 times as the area becomes 4 times.
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