a drop of olive oil of radius 0.25mm, spreads into a circular film of diameter 20cm on the water surface. estimate the size of oil molecule.
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olive oil drop radius = 0.25 mm
volume = 4/3 π 0.25³ mm³
Circular film radius = 100 mm
surface Area of the film on water = π 100² mm²
Thickness of the oil film on top of water surface
= 20.83 * 10⁻⁷ mm
= 2.083 nano meters
volume = 4/3 π 0.25³ mm³
Circular film radius = 100 mm
surface Area of the film on water = π 100² mm²
Thickness of the oil film on top of water surface
= 20.83 * 10⁻⁷ mm
= 2.083 nano meters
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