Question

A current of 9.65 A is passed through an aqueous
solution of NaCl using suitable electrodes for 1000
s. Given that 1 faraday equals 96500 C the amount
of NaOH (mol wt. 40.00) formed on electrolysis
is :
(1) 2.0 g
(2) 8.0 g
(3) 4.0 g
(4) 1.0 g.​

Answer 1

Explanation:

as per Faraday's law of electrlysis

mass of substance deposited

= I*t*M/(F*z)

= 9.65*1000*40/(96500*1) = 4 g

option 3 is correct