A cylinder of 20liter capacity contains a gas at 100 atm pressure how many flasks of 200 cm^3 capacity can filled from at 1 atm pressure temperature remains constant
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Answered by
5
Hey there,
For a given quantity of a gas at constant temperature,
P x V = a constant value (See 'Boyle's Law')
So if the initial and final conditions of pressure and volume are given by P1, V1, P2 and V2
Then P1 x V1 = P2 x V2
So, 100atm x 20000cm^3 = 1atm x V2cm^3
So V2 = 10^2 x 2 x10^4 / 1 = 2 x 10^6 cm^3
Since each flask has a capacity of 200cm^3
Number of flasks filled = 2 x 10^6 / 2 x 10^2 = 10^4
So, 10000 flasks can be filled.
Hope this helps!
For a given quantity of a gas at constant temperature,
P x V = a constant value (See 'Boyle's Law')
So if the initial and final conditions of pressure and volume are given by P1, V1, P2 and V2
Then P1 x V1 = P2 x V2
So, 100atm x 20000cm^3 = 1atm x V2cm^3
So V2 = 10^2 x 2 x10^4 / 1 = 2 x 10^6 cm^3
Since each flask has a capacity of 200cm^3
Number of flasks filled = 2 x 10^6 / 2 x 10^2 = 10^4
So, 10000 flasks can be filled.
Hope this helps!
Answered by
0
At constant temperaturePV = ConstantP₁V₁ = P₂V₂100atm × 20L = 1 atm × V₂V₂ = 100 × 20 LV₂ = 2000 LTotal volume that can be filled from that cylinder is 2000LVolume of each flask = 200 cm³ = 0.2LNo. of flask that can be filled = 2000 L / 0.2 L= 10,000∴ Ten thousand flask can be filled from that cylinder.
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