Question

The sum of the present ages of son and father is 60 years . six years hence father's age will be twice his sons present age . then fathers present age is ____ years.

Answer 1

Now, if son's age is x years , then father's age is (60-x) years.
6 years later son's age will be (6+x) years and father's age will be (6+60-x) years.
According to question ,
6+60-x=2×(6+x)
or, 66-x=12+2x
or, 66-12=2x+x
or, 54=3x
or, x=54/3=18
.'.Now son's age is 18 years.
.'.Father's present age is 60-18=42 years.

Answer 2

$\bf\large{\underline{Question:-}}$

The sum of the present ages of son and father is 60 years . six years hence father's age will be twice his sons present age . then fathers present age is.

$\bf\large{\underline{Solution:-}}$

Let,

• The present age of father be = x
• And present age of son be = y

Sum of their age = 60

After 6 years ago father age will twice of the son

• Find present age of father = ?

→ x + y = 60

→ x = 60 - y

→ x + 6 = 2 ( y + 6 )

→ x + 6 = 2y + 12

→ x = 2y + 12 - 6

→ x = 2y + 6

Also,

→ x = 60 - y ( putting value of x )

→ 2y + 6 = 60 - y

→ 2y + y = 60 - 6

→ 3y = 54

→ y = 54/3

→ y = 18

$\bf\large{\underline{Hence:-}}$

• Present age of son y = 18 years
• Present age of father x = 60 - y = 60 - 18 = 42 years