A cylinder of radius 12 cm contains water to a depth of 20 cm a spherical iron ball is dropped in to the cylinder and thus the level of water is raised by 6.75 cm find the radius
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Radius of the cylinder = 12 cm
Height of the cylinder = 6.75 cm
Let 'r' be the radius of the spherical iron ball.
Volume of the cylinder = volume of the spherical iron ball
πr²h = 4/3πr³
22/7×12×12×6.75 = 4/3×22/7×r³
3 × 12 × 12 × 6.75 = 4r³
2916 = 4r³
r³ = 2916/4
r³ = 729
r = 9 cm
So, the radius of the spherical iron ball is 9 cm.
Key concept:-
Radius :- A half straight line from the centre to the circumference of a circle sphere.
Circumference :- The outer boundary of a circle is known as circumference.
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