A cylinderical bucket with base radius 15 cm is filled with water up to a height of 20 cm .A heavy iron spherical ball of radius 9 cm is dropped into the bucket to submerge completelyin the water .Find the increase in the level of water.
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The volume of water raised is equal to the volume of the sphere. This is the core concept.
We need to find the volume of the water raised, which is a cylinder of height h and radius 15 cm.
V = pi * (r^2) * h
Also, the volume of sphere of radius 9 cm can also be found easily.
V = (4/3) * pi 8 (r^3)
Equate both and we get the value of h which is the level of the water raised.
Please let me know if you face any difficulty.
We need to find the volume of the water raised, which is a cylinder of height h and radius 15 cm.
V = pi * (r^2) * h
Also, the volume of sphere of radius 9 cm can also be found easily.
V = (4/3) * pi 8 (r^3)
Equate both and we get the value of h which is the level of the water raised.
Please let me know if you face any difficulty.
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Water level increased by 4.32 cm
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